django admin super(type, obj) -

well, let me explain this.

i working on simple django admin project.

in admin.py file, have following admin classes:

class a_admin(admin.modeladmin):     #some stuff   class b_admin(admin.modeladmin):     #some stuff 

i want override get_urls() method of a_admin if click button on a_admin instance change page, redirect page b_admin changelist page.

(i know there many ways want , mentioned above not best, want. let skip discussion why insist on solution.)

i want following:

def get_urls(self):     #django's code     #inside urlpattern     urlpattern = (         #default urls django admin         .....         url(r'^some_url$',             wrap(super(b_admin, self).changelist_view),             name='%s_%s_delete' % info),         ....)      return urlpatterns 

this not working, since 'self' a_admin class object rather b_admin obejct.

so there way proxy of calss a_admin inside b_admin? wanna override changelist_view of , call inside b.

is possible?

thanks in advance

you should instantiate b_admin , use method.

i believe following code should work:

from django.contrib import admin my_app.models import b_model  # model b_admin used  def get_urls(self):     #django's code     #inside urlpattern     urlpattern = (         #default urls django admin         .....         url(r'^some_url$',             wrap(b_admin(b_model, admin.site).changelist_view),             name='%s_%s_delete' % info),         ....)  return urlpatterns 

update: probably, b_admin instantiated when called

admin.site.register(b_model, b_admin) 

so instead of doing

b_admin(b_model, admin.site) 

again can adminsite's registry:

admin.site._registry[b_model]