android - how to avoid overlapping of dynamically positioned views -


how avoid overlapping of dynamically positioned views?

i have relativelayout , , adding views dynamically(at runtime) @ particular position(x,y coordinates) problem views overlapping. how avoid this.

thanks in advance.enter image description here

    <scrollview     android:layout_width="fill_parent"     android:layout_height="wrap_content" >     <linearlayout     android:layout_width="fill_parent"     android:layout_height="wrap_content"     android:orientation="vertical" >           <relativelayout             android:id="@+id/rl_main"             android:layout_width="fill_parent"             android:layout_height="wrap_content"             android:orientation="vertical" >         </relativelayout>          <linearlayout     android:layout_width="fill_parent"     android:id="@+id/ll_mainbottom"     android:layout_height="wrap_content"     android:orientation="vertical" >     </linearlayout>          </linearlayout>        </scrollview>

javacode

 ll_main = (relativelayout) findviewbyid(r.id.rl_main);              if (views[3].equals("textview")) {                   textview tv_new = new textview(tenminactivity.this);                 // location                 int x = integer.parseint(views[12]);                 int y = integer.parseint(views[13]);                  string bgcolor = "#" + views[4];                 string fgcolor = "#" + views[5];              tv_new.setbackgroundcolor(color.parsecolor(bgcolor)); // bg color         tv_new.settextcolor(color.parsecolor(fgcolor)); // text color                   relativelayout.layoutparams params = new relativelayout.layoutparams(             width, android.view.viewgroup.layoutparams.wrap_content);     params.leftmargin = x;     params.topmargin = y;                  ll_main.addview(tv_new, params); }else if(views[3].equals("edittext")){      ....  }

give 

android:paddingleft=""

and each element ones left of screen have bit of space. , ones right,give

android:paddingbottom=""

first,check first 2 elements name text , text field after can proceed rest.

i can guide better,if post code

check this,

<relativelayout xmlns:android="http://schemas.android.com/apk/res/android"     xmlns:tools="http://schemas.android.com/tools"     android:layout_width="match_parent"     android:layout_height="match_parent"     tools:context=".mainactivity" >      <textview         android:id="@+id/textview1"         android:layout_width="wrap_content"         android:layout_height="wrap_content"         android:padding="5dp"         android:text="name"         android:textsize="18sp" />      <edittext         android:id="@+id/edittext1"         android:layout_width="wrap_content"         android:layout_height="wrap_content"         android:layout_alignbottom="@+id/textview1"         android:layout_alignparenttop="true"         android:layout_marginleft="21dp"         android:layout_torightof="@+id/textview1"         android:ems="10"         android:padding="10dp"         android:paddingl="10dp" >          <requestfocus />     </edittext>  </relativelayout>

Comments

Post a Comment

Popular posts from this blog

jquery - How can I dynamically add a browser tab? -

since using iframes house external pages are, accounts "not preferred method" , disallowed sites (flickr, one), want dynamically generate browser tabs. e.g., when user submits form, want dynamically generate tab on browser in response submitted. e.g., might want add new tab url like: http://www.bigsurgarrapata.com/contact how in jquery? you want form target attribute action attribute. http://www.w3schools.com/tags/att_form_target.asp browsers have ultimate control on result of target attribute open new tab value of _blank. <form action="contact_submit.php" target="_blank" method="post">
Read more

keyboard - C++ GetAsyncKeyState alternative -

i using windows.h library's getasynckeystate function define key pushed on keyboard . here program returns int value of pushed key example. #include <iostream> #include <windows.h> using namespace std; int main (){ char i; for(i=8;i<190;i++){ if(getasynckeystate(i)== -32767){ cout<<int (i)<<endl; } } return 0; } but trying make opengl simple game , function appeared slow . there function not need cycle 180 times , if statement . thanks you're trying make opengl game, you're going use glfw. if that's case can away using glfwgetkey() such: if (glfwgetkey(glfw_key_up) == glfw_press) {...} if (glfwgetkey(glfw_key_down) == glfw_press) {...} that method nicely explained in tutorial 6 opengl-tutorial.org . should start first tutorial of beginners tutorials , later intermediate tutorials . if you're going make win32 window can listen wm_keydown or wm_keyup messages , virtua...
Read more

android - java.net.UnknownHostException(Unable to resolve host “URL”: No address associated with hostname) -

i developing app testing asp.net webservice in android.for simple webservice adding 2 numbers used.where numbers passed parameters.the result in dialogue.the webserver works in local. when application runs following result exception.i provided internet permission in manifest. java.net.unknownhostexception(unable resolve host “ http://url.com/ ”: no address associated hostname) my code given below main activity public static string rslt=""; /** called when activity first created. */ @override public void oncreate(bundle savedinstancestate) { super.oncreate(savedinstancestate); setcontentview(r.layout.activity_main); button b1=(button)findviewbyid(r.id.button1); final alertdialog ad=new alertdialog.builder(this).create(); b1.setonclicklistener(new onclicklistener() { @override public void onclick(view arg0) { // todo auto-generated method stub try { ...
Read more