r - Dichotomize data by factor -


i need create dichtomized variable based on 2 factors (one hopes it's possible).

let's have data:

    d <- data.frame (      agegroup = c(2,1,1,2,3,2,1,3,3,3,3,3,1,1,2,3,2,1,1,2,1,2,2,3) ,     gender = c(2,2,2,2,2,2,1,2,1,1,1,2,1,1,2,2,1,1,1,1,2,1,1,1) ,      hourwalking = c(0.3,0.5,1.1,1.1,1.1,1.2,1.2,1.2,1.3,1.5,1.7,1.8,2.1,2.1,2.2,2.2,2.3,2.4,2.4,3,3.1,3.1,4.3,5)             )

i create binary (lowwalkhrs) using gender- , agegroup-specific median (e.g., when agegroup = 1 , gender = 1, median = 2.1 (median found using excel)). lowwalkhrs added variable in dataset, output be:

     agegroup gender hourwalk lowwalkhrs         2       2       0.3       1         1       2       0.5       1         1       2       1.1       0         2       2       1.1       1         3       2       1.1       1         2       2       1.2       0         1       1       1.2       1           ....         3       1       5         0

i have rather large dataset (~10k observations), excel out of question.

in r i've tried cut , cut2, doesn't seem take factor variables, ddply, gave me error message of (error in $<-.data.frame(*tmp*, "lowwalkhrs", value = list(hourwalking = c(0.63, : replacement has 949 rows, data has 11303).

i suspect might slow, think works:

z <- mapply(d$agegroup, d$gender, d$hourwalking, fun=function(a,g,h)     as.numeric(h < median(d$hourwalking[d$agegroup==a & d$gender==g])) )

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