assembly - LC3 Machine language -


in lc-3 machine language how can number of 16 bits left shifted n bits? if have 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 , binary numbers | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0 | 1 |

then how can left shift 3?

because lc-3 apparently has no shift operations have yourself.

some folks dicussing lc-3 simulator , bit shift operations here http://www.asmcommunity.net/board/index.php?topic=28978.0 indicate that:

for each bit position of shift left, multiply 2 (or add if like)

hope helps.


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