printing - print matrix with indicies python -


i have matrix in python defined this: 

matrix = [['a']*4 in range(4)]

how print in following format:

   0  1  2  3 0     1     2     3

this function matches exact output.

>>> def printmatrix(testmatrix):         print ' ',         in range(len(testmatrix[1])):  # make work non square matrices.               print i,         print         i, element in enumerate(testmatrix):               print i, ' '.join(element) >>> matrix = [['a']*4 in range(4)] >>> printmatrix(matrix)   0 1 2 3 0 a a 1 a a 2 a a 3 a a >>> matrix = [['a']*6 in range(4)] >>> printmatrix(matrix)   0 1 2 3 4 5 0 a a a 1 a a a 2 a a a 3 a a a

to check single length elements , put & in place of elements length > 1, put check in list comprehension, code change follows.

>>> def printmatrix2(testmatrix):     print ' ',     in range(len(testmatrix[1])):         print i,     print     i, element in enumerate(testmatrix):         print i, ' '.join([elem if len(elem) == 1 else '&' elem in element]) >>> matrix = [['a']*6 in range(4)] >>> matrix[1][1] = 'ab' >>> printmatrix(matrix)   0 1 2 3 4 5 0 a a a 1 ab a a 2 a a a 3 a a a >>> printmatrix2(matrix)   0 1 2 3 4 5 0 a a a 1 & a a 2 a a a 3 a a a

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