osx - Hosts file missing on Mac OS X - Xcode Failing to compile code -


i've tried run first objective-c code in xcode... compilation process successfully, error returns " invalid host string: 'localhost' ".

after googling, found out , connected points might had hosts file deleted.

now cannot recreate /etc/hosts through terminal using:

sudo cat >/etc/hosts <

#

host database

#

localhost used configure loopback interface

when system booting. not change entry.

#

127.0.0.1 localhost 255.255.255.255 broadcasthost ::1 localhost fe80::1%1o0 localhost eod sudo: /private/etc/sudoers mode 0666, should 0440

thanks in advance workaround.

you have broken system making inappropriate changes.

first, need fix permissions on /etc/sudoers. might try opening disk utility, selecting system volume, , clicking repair disk permissions. not sure change sudoers permissions. if not, reboot system , press , hold command , s keys. boots single-user mode. when command prompt appears, enter these commands:

mount -uw / chmod 0666 /etc/sudoers reboot

when system boots, sudo command might working again, if have not otherwise broken it. @ point, may able recreate /etc/hosts. in addition restoring contents, may need set ownership , permissions:

sudo chown root:wheel /etc/hosts sudo chmod u=rw,go=r /etc/hosts

you restore /etc/hosts while in single-user mode, rather booting , using sudo command. before reboot command, use cat (or cp copy file prepared previously) recreate /etc/hosts, execute chown , chmod commands (without sudo), reboot.

i cannot guarantee these commands suffice or there no errors; diagnosing problems such remotely troublesome.

stop tinkering system without making backups know work or taking other steps able revert changes.


Comments

Post a Comment

Popular posts from this blog

Change php variable from jquery value using ajax (same page) -

what i'm trying this: i've php global variable $currentid , simple jquery script check if there "id" (page) in hash of url , if yes wanted give value $currentid . i've been reading lot , notice shall use ajax i'm not managing it. my code is: <script type="text/javascript"> $(document).ready(function(){ if (parent.location.hash != '' ) { var thecurrentid = parent.location.hash.split('#')[1]; $.ajax({ url: 'my.php', //current page type: 'post', data: {theid: thecurrentid }, datatype: 'json', success: function () { } }); } // code here }); </script> could me please? thank in advance. php server side language, meaning once has sent data browser, php variables , data cannot changed... however, using ajax, can send request php page , change data in dom based on result. consider th...
Read more

How can I fetch data from a web server in an android application? -

i want retrieve data web server in android application, , don't know begin. should use web services? i recommend these tutorials: connect android php , mysql , json in android , php , mysqli i used these tutorials , managed trying working without difficulty. between them describe each step in how attempting @ each stage, android application, database , web server side , has information included can process , use received information the thing add connect android php , mysql tutorial makes use of mysql_ in php deprecated. better use mysqli why included third link. the basic outline of want this: 1) in android app make request server php script using class this: import java.io.bufferedreader; import java.io.ioexception; import java.io.inputstream; import java.io.inputstreamreader; import java.io.unsupportedencodingexception; import java.util.list; import org.apache.http.httpentity; import org.apache.http.httpresponse; import org.apache.http.namevaluepair...
Read more

jquery - How can I dynamically add a browser tab? -

since using iframes house external pages are, accounts "not preferred method" , disallowed sites (flickr, one), want dynamically generate browser tabs. e.g., when user submits form, want dynamically generate tab on browser in response submitted. e.g., might want add new tab url like: http://www.bigsurgarrapata.com/contact how in jquery? you want form target attribute action attribute. http://www.w3schools.com/tags/att_form_target.asp browsers have ultimate control on result of target attribute open new tab value of _blank. <form action="contact_submit.php" target="_blank" method="post">
Read more