java - How to change a JTextField based on a JComboBox selection -


this silly program working on school having trouble. have jcombobox , based on user selects want change text field. i'm having trouble however, stands program compiles , runs text field doesn't change. i've found plenty of examples of people doing far more complicated things need simple solution. here code. thanks!

import javax.swing.*; import java.awt.*; import java.awt.event.*;  public class emocon extends jframe implements itemlistener { jpanel row1 = new jpanel(); jcombobox choose = new jcombobox(); jpanel row2 = new jpanel(); jtextfield text = new jtextfield(10); //image displayed here jpanel row3 = new jpanel(); jlabel pic = new jlabel();  //images imageicon happy = new imageicon("images/happy.gif"); imageicon lol = new imageicon("images/lol.gif"); imageicon winky = new imageicon("images/winky.gif"); imageicon sad = new imageicon("images/sad.gif"); imageicon worried = new imageicon("images/worried.gif"); imageicon angry = new imageicon("images/angry.gif"); imageicon shock = new imageicon("images/shock.gif"); imageicon uninpressed = new imageicon("images/uninpressed.gif"); imageicon yawn = new imageicon("images/yawn.gif"); imageicon evil = new imageicon("images/evil.gif");  public emocon(){     settitle("emoticon converter");     setsize(350,350);     setdefaultcloseoperation(jframe.exit_on_close);     setvisible(true);  gridlayout 2 = new gridlayout(3,1); setlayout(two);  choose.additem("happy");  choose.additem("lol");  choose.additem("winky");  choose.additem("sad");  choose.additem("worried");  choose.additem("angry");  choose.additem("shock");  choose.additem("uninpressed");  choose.additem("yawn");  choose.additem("evil"); choose.additemlistener(this); row1.add(choose); row2.add(text); row3.add(pic);  add(row1); add(row2); add(row3);  } @override public void itemstatechanged(itemevent item) { object source = item.getsource(); string emo = source.tostring(); if (emo == "sad"){     text.settext("hjgjhg"); } }    public static void main(string[] args) {     emocon emo = new emocon(); } }

you've problem here:

if (emo == "sad"){     text.settext("hjgjhg"); }

don't compare strings using ==. use equals(...) or equalsignorecase(...) method instead. understand == checks if 2 objects same not you're interested in. methods on other hand check if 2 strings have same characters in same order, , that's matters here. instead of

if (fu == "bar") {   // }

do, 

if ("bar".equals(fu)) {   // }

or,

if ("bar".equalsignorecase(fu)) {   // }

edit

your other problem you're getting source itemevent. source jcombobox, not want. need selected item!

try using different method available in itemevent object, not getsource().


Comments

Post a Comment

Popular posts from this blog

jquery - How can I dynamically add a browser tab? -

since using iframes house external pages are, accounts "not preferred method" , disallowed sites (flickr, one), want dynamically generate browser tabs. e.g., when user submits form, want dynamically generate tab on browser in response submitted. e.g., might want add new tab url like: http://www.bigsurgarrapata.com/contact how in jquery? you want form target attribute action attribute. http://www.w3schools.com/tags/att_form_target.asp browsers have ultimate control on result of target attribute open new tab value of _blank. <form action="contact_submit.php" target="_blank" method="post">
Read more

node.js - Getting the socket id,user id pair of a logged in user(s) -

i have web application done using node js , in it,i have authentication system requires users log in before can access pages. have 2 pages,the homepage , updates page. from read docs,a new socket id issued when user opens tab in browser. me being admin,i know socket id of logged in user , more so,the socket id,logged in user id pair logged in users. what method can use socket id,logged in user id pair make sure broadcast realtime info users online?.
Read more

keyboard - C++ GetAsyncKeyState alternative -

i using windows.h library's getasynckeystate function define key pushed on keyboard . here program returns int value of pushed key example. #include <iostream> #include <windows.h> using namespace std; int main (){ char i; for(i=8;i<190;i++){ if(getasynckeystate(i)== -32767){ cout<<int (i)<<endl; } } return 0; } but trying make opengl simple game , function appeared slow . there function not need cycle 180 times , if statement . thanks you're trying make opengl game, you're going use glfw. if that's case can away using glfwgetkey() such: if (glfwgetkey(glfw_key_up) == glfw_press) {...} if (glfwgetkey(glfw_key_down) == glfw_press) {...} that method nicely explained in tutorial 6 opengl-tutorial.org . should start first tutorial of beginners tutorials , later intermediate tutorials . if you're going make win32 window can listen wm_keydown or wm_keyup messages , virtua
Read more