java - Getting IP address of client -

i developing web application using jsp, servlets (container: glassfish) in need clients ip address.

i getting clients ip address, because want give access pages (like customer maintenance forms) on computers withing office, want restrict access pages outside office.

following code far:

way1

string ipaddress =  request.getremoteaddr(); system.out.println("ip address: "+ipaddress); 

way2

string ipaddress=null; string getway = request.getheader("via");   // gateway ipaddress = request.getheader("x-forwarded-for");   // proxy if(ipaddress==null) {     ipaddress = request.getremoteaddr(); } system.out.println("ip address: "+ipaddress); 

above code gives me different ip address each time when restart computer (shutdown->start or restart).

i getting ip6 like:

fe80:0:0:0:20ca:1776:f5ff:ff15%13 

let me know wrong code?

as @martin , this answer explained, complicated. there no bullet-proof way of getting client's ip address.

the best can try parse "x-forwarded-for" , rely on request.getremoteaddr();

public static string getclientipaddress(httpservletrequest request) {     string xforwardedforheader = request.getheader("x-forwarded-for");     if (xforwardedforheader == null) {         return request.getremoteaddr();     } else {         // of https://en.wikipedia.org/wiki/x-forwarded-for         // general format of field is: x-forwarded-for: client, proxy1, proxy2 ...         // want client         return new stringtokenizer(xforwardedforheader, ",").nexttoken().trim();     } }