ubuntu - Efficient way to draw 3! ( 6 times) three shapes in C -
i want draw combinations (3! = 6) of 3 shapes , in 1 row : empty cell , x , or rectangle .
the current code :
for empty cell :
void drawemptycell() { printf("||||||||||||||||||||||||||\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("| |\n"); printf("||||||||||||||||||||||||||\n"); } for cell rectangle :
void drawcellwithrectangle() { printf("||||||||||||||||||||||||||\n"); printf("| |\n"); printf("| |\n"); printf("| ************** |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| ************** |\n"); printf("| |\n"); printf("| |\n"); printf("||||||||||||||||||||||||||\n"); } and cell x :
void drawcellwithx() { printf("||||||||||||||||||||||||||\n"); printf("| |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| * * |\n"); printf("| |\n"); printf("||||||||||||||||||||||||||\n"); } i can use brute force way , take 6 options , example :
void drawoption1() { // empty , rectangle , x printf("||||||||||||||||||||||||||");printf("||||||||||||||||||||||||||");printf("||||||||||||||||||||||||||\n"); printf("| |");printf("| |");printf("| |\n"); printf("| |");printf("| |");printf("| * * |\n"); printf("| |");printf("| ************** |");printf("| * * |\n"); printf("| |");printf("| * * |");printf("| * * |\n"); printf("| |");printf("| * * |");printf("| * * |\n"); printf("| |");printf("| * * |");printf("| * |\n"); printf("| |");printf("| * * |");printf("| * * |\n"); printf("| |");printf("| * * |");printf("| * * |\n"); printf("| |");printf("| ************** |");printf("| * * |\n"); printf("| |");printf("| |");printf("| * * |\n"); printf("| |");printf("| |");printf("| |\n"); printf("||||||||||||||||||||||||||");printf("||||||||||||||||||||||||||");printf("||||||||||||||||||||||||||\n"); } but i'm looking else , without brute force way .
any suggestions appreciated .
a approach put shapes string array. appropriate algorithm draw them
something following job. hope idea
char* x[] = { "||||||||||||||||||||||||||", "| |", "| * * |", "| * * |", "| * * |", "| * * |", "| * |", "| * * |", "| * * |", "| * * |", "| * * |", "| |", "||||||||||||||||||||||||||"}; char* o[] .. char* empty[] .. .. output (" xo"); .. void output (const char* pout) { // assert (sizeof(x) == sizeof(o)); // assert (sizeof(x) == sizeof(empty)); int i, j; (i = 0; < sizeof(o) / sizeof(o[0]); ++) { const char* c = pout; while (*c != 0) { switch (*c ++) { case 'x': printf (x[i]); break; case 'o': printf (o[i]); break; default: printf (empty[i]); break; } } printf ("\n"); } } obviously x,o, empty required hold same number of line.
now in c, no compiled yet, may have errors
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