Compare date via shell script -


i have text:

aaaaaaaaaaaaaaaaaaaaddddd sadasdafnsdfoisjhpfnsf dasnfdfmsdf until: thu apr 29 19:41:02 eest 2021 dasd asdasmda[mfiun[hg[sm df, dfmsdf[ismdfsdfsd,flsdfsdf******************

i have parse date text , after have compare today , if greater otherwise have else , have write in shell script not well. can give me example how it.

thanks in advance.

i in 2 steps. (it done in one):

1, date string 2, comparison

e.g.:

 kent$  d=$(echo "aaaaaaaaaaaaaaaaaaaaddddd sadasdafnsdfoisjhpfnsf dasnfdfmsdf until: thu apr 29 19:41:02 eest 2021 dasd asdasmda[mfiun[hg[sm df, dfmsdf[ismdfsdfsd,flsdfsdf******************"|grep -o '[a-z].*[0-9]')

check var d:

kent$  echo $d thu apr 29 19:41:02 eest 2021

now compare date today. need convert both dates seconds comparison:

kent$  echo $(($(date -d"${d}" +%s)-$(date +%s))) 251171977

i printed result of above command out. in case, assign var. or check result directly. if >0 means date in text in future. otherwise, in past(or same today).

edit

some math:

with int:

kent$  echo $((251171977/(3600*24))) 2907

with precision: 

kent$  echo "scale=2;251171977/(3600*24)"|bc  2907.08

more precisely:

kent$  echo "scale=7;251171977/(3600*24)"|bc                                                                                                                                 2907.0830671

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