bash - Using single variable to pass in reference to multiple field variables in awk? -


i'd pass reference number of field variables awk , have print out value each variable each line without using loop.

for example, i'd like:

var=$1":"$3":"$4 echo "aa bb cc dd" | awk -v var=$var '{print var}'

i output of "aa:cc:dd." when try as-is, output of $1":"$3":"$4. possible number of field variables in var without doing loop?

var='$1":"$3":"$4' echo "aa bb cc dd" | awk  "{print $var}"

this pass variables want literal awk print format i.e

echo "aa bb cc dd" | awk {print $1":"$3":"$4}

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