php - Replacing string with variables stored in an array -


ok i'm unsure syntax on one, think logic self explanatory i'm unsure if preg_replace work or whether loop needed end result.

$string = $randomizer->fecthrandomphrase($cfg['seo']['meta']['descriptions']['single'], 3, $_server['request_uri']);

returns string

lorem ipsum dolor sit amet,[address1], [address2], [postcode]. consectetur adipiscing elit. mauris id dui sem, eget laoreet tellus. vivamus lacinia vestibulum odio lobortis - [region]

i search string parts want change;

$find = array('[address1]','[address2]','[postcode]','[region]');

i pull information stored in these variables , place them in array;

$replace = array($address1,$address2,$postcode,$region);

the before returning phrase apply preg_replace swap on info have stored

$phrase = preg_replace($find,$replace,$string);

do need loop through array $replace allow reading of each variable , replace work or using wrong function entirely?

str_replace() can take arrays first 2 parameters, might want consider instead. otherwise, you'd need form proper regex $find in order invoke preg_replace() once, not doing.

usage:

$phrase = str_replace( $find, $replace, $string);

now $phrase shoud contain desired output.


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