python - pyodbc connect to database twice and failed -


i'm trying use python , pyodbc access sql server 2008. first connection works. then, after program finishes job, closes connection. when program tries access database , connect again, fails in statement:

self.conn = pyodbc.connect(driver=self.driver, server=self.server, database=self.database, uid=self.uid, pwd=self.pwd, charset="utf-8")

but first time ok. know why? below python code:

class odbc_ms:        def __init__(self, driver,server, database, uid, pwd):         ''' initialization '''          self.driver = driver         self.server = server         self.database = database         self.uid = uid         self.pwd = pwd       def _getconnect(self):         ''' connect db '''         if not self.database:             raise(nameerror,"no getting db name")         try:             self.conn = pyodbc.connect(driver=self.driver, server=self.server,                                        database=self.database, uid=self.uid,                                        pwd=self.pwd, charset="utf-8")         except exception,e:             print e.message         else:             self.cur = self.conn.cursor()             if not self.cur:                 raise(nameerror,"connected failed!")             else:                 return self.cur, self.conn      def execnoquery(self,conn, cursor, sql):         cursor.execute(sql)         ret = conn.commit()         return ret      def _unconnect(self,conn, cursor):         conn.close()       if __name__ == '__main__':      ms = odbc_ms('{sql server}', r'<server>', '<db>', '<user>',  '<password>')      cursor, conn = ms._getconnect() #connection      sql = "create table xx example"      ret = ms.execnoquery(conn, cursor,sql) #sql operation       ms._unconnect(conn, cursor) #close db       #access database second time.     ms = odbc_ms('{sql server}', r'<server>', '<db>', '<user>',  '<password>')      cursor, conn = ms._getconnect() # not success, don't know why      sql = "create table xx example"     ret = ms.execnoquery(conn, cursor,sql) #sql operation      ms._unconnect(conn, cursor) #close db

the second time when program calls ms.getconnect(), statement self.conn = pyodbc.connect(driver=self.driver, server=self.server, database=self.database, uid=self.uid, pwd=self.pwd, charset="utf-8") fails.


Comments

Post a Comment

Popular posts from this blog

jquery - How can I dynamically add a browser tab? -

since using iframes house external pages are, accounts "not preferred method" , disallowed sites (flickr, one), want dynamically generate browser tabs. e.g., when user submits form, want dynamically generate tab on browser in response submitted. e.g., might want add new tab url like: http://www.bigsurgarrapata.com/contact how in jquery? you want form target attribute action attribute. http://www.w3schools.com/tags/att_form_target.asp browsers have ultimate control on result of target attribute open new tab value of _blank. <form action="contact_submit.php" target="_blank" method="post">
Read more

keyboard - C++ GetAsyncKeyState alternative -

i using windows.h library's getasynckeystate function define key pushed on keyboard . here program returns int value of pushed key example. #include <iostream> #include <windows.h> using namespace std; int main (){ char i; for(i=8;i<190;i++){ if(getasynckeystate(i)== -32767){ cout<<int (i)<<endl; } } return 0; } but trying make opengl simple game , function appeared slow . there function not need cycle 180 times , if statement . thanks you're trying make opengl game, you're going use glfw. if that's case can away using glfwgetkey() such: if (glfwgetkey(glfw_key_up) == glfw_press) {...} if (glfwgetkey(glfw_key_down) == glfw_press) {...} that method nicely explained in tutorial 6 opengl-tutorial.org . should start first tutorial of beginners tutorials , later intermediate tutorials . if you're going make win32 window can listen wm_keydown or wm_keyup messages , virtua...
Read more

android - java.net.UnknownHostException(Unable to resolve host “URL”: No address associated with hostname) -

i developing app testing asp.net webservice in android.for simple webservice adding 2 numbers used.where numbers passed parameters.the result in dialogue.the webserver works in local. when application runs following result exception.i provided internet permission in manifest. java.net.unknownhostexception(unable resolve host “ http://url.com/ ”: no address associated hostname) my code given below main activity public static string rslt=""; /** called when activity first created. */ @override public void oncreate(bundle savedinstancestate) { super.oncreate(savedinstancestate); setcontentview(r.layout.activity_main); button b1=(button)findviewbyid(r.id.button1); final alertdialog ad=new alertdialog.builder(this).create(); b1.setonclicklistener(new onclicklistener() { @override public void onclick(view arg0) { // todo auto-generated method stub try { ...
Read more