java - Regarding float type precision -


i can't understand why this

float f = integer.max_value; system.out.println(integer.max_value); system.out.println((int)f);

produces same lines,

as why 

float f2 = (float) integer.max_value; system.out.println(integer.max_value); system.out.println(f2.intvalue());

i mean, mantissa length floating point number 2^23-1. how manage keep max_value of integer, 2^31 - 1?

how manage keep max_value of integer, 2^31 - 1?

it doesn't. value of f 2147483648.

however, narrowing primitive conversion float int clamps value. gets part:

  • otherwise, 1 of following 2 cases must true:

    • the value must small (a negative value of large magnitude or negative infinity), , result of first step smallest representable value of type int or long.

    • the value must large (a positive value of large magnitude or positive infinity), , result of first step largest representable value of type int or long.

you can see making number bigger:

float f = integer.max_value; f = f * 1000; system.out.println(integer.max_value); // 2147483647 system.out.println((int)f); // 2147483647

or casting long instead, doesn't need clamped @ same point:

float f = integer.max_value; system.out.println(integer.max_value); // 2147483647 system.out.println((long)f); // 2147483648

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