PHP and mySQL Dynamic Query -


im trying create dynamic query based upon or selections option values selected user. eg if select project id query return project id, size , lesson stored in second table, or if select size , department query execute. displaying projects of chosen size lessons against it.

heres ive got far. help.

<?php  $pid = $_post['project_id'] ; $psize = $_post['projectsize'] ; $pdepts = $_post['depts'] ; $lstage = $_post['stage'] ; $ltype = $_post['type'] ; $impacted = $_post['impacted'] ;   $sqlstring = null; echo "total number of captured post variables is:"; echo count($_post);  echo '<br />';   $number = 0;  foreach ($_post $param_name => $param_val ) {  if ($param_val ==""){      }else{       $number++;     }  echo "param: $param_name = $param_val<br />\n"; } if($number ==1) {  }else{  }  ?>

i hope can little , added array check , need check security , injection :) 

<?php  $pid = $_post['project_id'] ; $psize = $_post['projectsize'] ; $pdepts = $_post['depts'] ; $lstage = $_post['stage'] ; $ltype = $_post['type'] ; $impacted = $_post['impacted'] ; //your columns in db  $columns = array('project_id'=>'project_id','project_size'=>'project_size','depts'=>'depts','stage'=>'stage');   $sqlstring = null; echo "total number of captured post variables is:"; echo count($_post);  echo '<br />';   $number = 0; $querystr = "";  $prestr = array();  foreach ($_post $key => $val ) {  if (!empty($_post[$key])){        if(!is_array($_post[$key]))            $currentstr = $columns[$key]." = ".$val;         else            $currentstr = $columns[$key]." in (".implode(',',$_post[$key]).")";          $prestr[] = $currentstr;     }  }  $querystr = "select * tablename ".implode(' , ',$prestr); echo $querystr;   if($number ==1) {  }else{  }  ?>

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