Does Python's time.time() return a timestamp in UTC? -


this question has answer here:

i need generate unix timestamp in utc time i'm using time.time() produce it.
need else or timestamp automatically in utc?

technically, time.time() doesn't specify, , practically, @ least in cpython, returns timestamp in whatever format used underlying standard c library's time function.

the c standard (which isn't freely available) doesn't whether gmt, , neither posix standard. says:

the time() function shall return value of time in seconds since epoch.

… without saying timezone, except can pass localtime or gmtime "broken-down time" in local or gmt timezones.

so, platform-specific. platform can return wants time, long in way makes localtime , gmtime work properly.

that being said, it's usually going gmt—or, rather, either utc (windows), or utc-except-for-leap-seconds (most other platforms). example, freebsd says:

the time() function returns value of time in seconds since 0 hours, 0 minutes, 0 seconds, january 1, 1970, coordinated universal time, without including leap seconds.

os x , other *bsds have same manpage, windows , linux/glibc return utc (with or without leap seconds), etc.

also, python documentation says:

to find out epoch is, @ gmtime(0).

putting definitions time , gmtime, more work platform return local timestamps gmt. (that being said, statement can't authoritative, because it's not quite true posix platform, leap seconds.)


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