nested - Wicket listview within a listview -


i pretty new wicket i'm making horrible mistake here.

i trying add listview listview receive error, know error has hierarchy of components , because hierarchy of java file , html file not same. don't know how solve it. give me pointers?

relevant code (setting listviews):

final listview<menuitem> sublistview = new listview<menuitem>("menusubview", new arraylist<menuitem>()) {     private static final long serialversionuid = 1l;      @override     protected void populateitem(listitem<menuitem> item) {         //do     } };  sublistview.setrenderbodyonly(true); sublistview.setreuseitems(true);  listview<menuitem> listview = new listview<menuitem>("menuview", menuitems) {     private static final long serialversionuid = 1l;      @override     protected void populateitem(listitem<menuitem> item) {     final menuitem menuitem = item.getmodelobject();     ajaxlink<menuitem> alink =  new ajaxlink<menuitem>("menuitemlink") {                 private static final long serialversionuid = 1l;                  @override                 public void onclick(ajaxrequesttarget target) {                     if(target != null) {                         //do                     }                 }     };      alink.add(new label("linktext", menuitem.gettext()));     item.add(alink);     item.add(sublistview); }

html:

<wicket:panel>     <ul wicket:id="menuview">         <li>             <a href="#" wicket:id="menuitemlink" >                 <span wicket:id="linktext"></span>             </a>                 <ul wicket:id="menusubview">                     <li>                         <div wicket:id="subitemtext"></div>                     </li>                 </ul>         </li>     </ul>

error:

unable find component id 'menusubview' in [listitem [component id = 0]] expected: 'viewerpanel:optionsmenu:menuview:0.menusubview'. found similar names: 'viewerpanel:optionsmenu:menuview:1:menusubview' markupstream: [markup = file:.../panels/menu/simplemenu.html

    • </li> --> , index = 9, current = '' (line 0, column 0)] @ org.apache.wicket.markup.markupstream.throwmarkupexception(markupstream.java:526) @ org.apache.wicket.markupcontainer.rendernext(markupcontainer.java:1435) ....

    thank in advance replying.

    kind regards, bram


    Comments

    Post a Comment

    Popular posts from this blog

    jquery - How can I dynamically add a browser tab? -

    since using iframes house external pages are, accounts "not preferred method" , disallowed sites (flickr, one), want dynamically generate browser tabs. e.g., when user submits form, want dynamically generate tab on browser in response submitted. e.g., might want add new tab url like: http://www.bigsurgarrapata.com/contact how in jquery? you want form target attribute action attribute. http://www.w3schools.com/tags/att_form_target.asp browsers have ultimate control on result of target attribute open new tab value of _blank. <form action="contact_submit.php" target="_blank" method="post">
    Read more

    keyboard - C++ GetAsyncKeyState alternative -

    i using windows.h library's getasynckeystate function define key pushed on keyboard . here program returns int value of pushed key example. #include <iostream> #include <windows.h> using namespace std; int main (){ char i; for(i=8;i<190;i++){ if(getasynckeystate(i)== -32767){ cout<<int (i)<<endl; } } return 0; } but trying make opengl simple game , function appeared slow . there function not need cycle 180 times , if statement . thanks you're trying make opengl game, you're going use glfw. if that's case can away using glfwgetkey() such: if (glfwgetkey(glfw_key_up) == glfw_press) {...} if (glfwgetkey(glfw_key_down) == glfw_press) {...} that method nicely explained in tutorial 6 opengl-tutorial.org . should start first tutorial of beginners tutorials , later intermediate tutorials . if you're going make win32 window can listen wm_keydown or wm_keyup messages , virtua...
    Read more

    android - java.net.UnknownHostException(Unable to resolve host “URL”: No address associated with hostname) -

    i developing app testing asp.net webservice in android.for simple webservice adding 2 numbers used.where numbers passed parameters.the result in dialogue.the webserver works in local. when application runs following result exception.i provided internet permission in manifest. java.net.unknownhostexception(unable resolve host “ http://url.com/ ”: no address associated hostname) my code given below main activity public static string rslt=""; /** called when activity first created. */ @override public void oncreate(bundle savedinstancestate) { super.oncreate(savedinstancestate); setcontentview(r.layout.activity_main); button b1=(button)findviewbyid(r.id.button1); final alertdialog ad=new alertdialog.builder(this).create(); b1.setonclicklistener(new onclicklistener() { @override public void onclick(view arg0) { // todo auto-generated method stub try { ...
    Read more