sql server 2008 - How to return consecutive date ranges frm a set of dates in sql -


i have set of dates table in sql. want return date ranges , need help.

so if had dates this

pk  - date                                       160 - 2013-04-16 12:09:00    160 - 2013-04-17 11:07:00    162 - 2013-04-16 12:10:00    160 - 2013-04-20 12:10:00

i want example 

pk   - beg                   -  end 160  -  2013-04-16 12:09:00  -  2013-04-17 11:07:00 160  -  2013-04-17 11:07:00  -  2013-04-20 12:10:00 162  -  2013-04-16 12:10:00  -  2013-04-16 12:10:00

can please me.

thank you

i using microsoft sql server management studio 10.0.1600.22

here's example using ms sql server 2008 (though should work 2005+):

with cte (   select rownum = row_number() on (partition pk order date asc), *   dates ) select   a.pk, a.date [beg], coalesce(b.date, a.date) [end]   cte   left join cte b     on b.pk = a.pk , b.rownum = a.rownum + 1   b.rownum not null or a.rownum = 1

this row numbers each pk, provide joins between table , itself, filtering out rows don't have match unless first row pk.

here's table:

create table dates (pk int, date datetime)  insert dates values   (160, '2013-04-16 12:09:00'),   (160, '2013-04-17 11:07:00'),   (162, '2013-04-16 12:10:00'),   (160, '2013-04-20 12:10:00')

sql fiddle here (hopefully - been having issues).


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