Printing X-type pattern in Python 2.7 -


i'm trying print pattern in python: 

    *............*     .**........**     ..***....***     ...********     ...********     ..***....***     .**........**     *............*

and came code job:

for row in range(1,5):     print "." * (row -1) + row * "*" + (16 - row * 4) * "." + row * "*" row in range (0,4):     print("." * (3-row)+ "*" *(4 -row) + row * 4 * "." +"*" *(4 -row))

my question: possible without using 2 loops? btw, not homework, i'm playing around exercises "think programmer" v. anton spraul , implementing solutions in python rather c++.

thanks in advance.

without changing else, can loop on 2 ranges:

for row in range(1,5)+range(4,0,-1):     print "." * (row -1) + row * "*" + (16 - row * 4) * "." + row * "*"

since can add lists together:

in [8]: range(1,5) out[8]: [1, 2, 3, 4]  in [9]: range(4,0,-1) out[9]: [4, 3, 2, 1]  in [10]: range(1,5) + range(4,0,-1) out[10]: [1, 2, 3, 4, 4, 3, 2, 1]

by way, can rid of leading dots using spaces:

for row in range(1,5)+range(4,0,-1):     print " " * (row -1) + row * "*" + (16 - row * 4) * "." + row * "*"  *............*  **........**   ***....***    ********    ********   ***....***  **........** *............*

a more elegant thing might build list of strings:

x = [] row in range(1,5):     x.append(" " * (row -1) + row * "*" + (16 - row * 4) * "." + row * "*")

now, add bottom half duplicating top half in reverse:

x = x + list(reversed(x))

but when print see list:

print x #['*............*', ' **........**', '  ***....***', '   ********', '   ********', '  ***....***', ' **........**', '*............*']

so can join them newlines:

print '\n'.join(x)  *............*  **........**   ***....***    ********    ********   ***....***  **........** *............*

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