java - a long bigger than Long.MAX_VALUE -


how can long number bigger long.max_value?

i want method return true:

public static isbiggerthanmaxlong(long l){        return l>long.max_value; }

um, method can't return true. that's point of long.max_value. really confusing if name were... false. should called long.some_fairly_large_value , have literally 0 reasonable uses. use android's isuseragoat, or may roll own function returns false.

note long in memory takes fixed number of bytes. from oracle:

long: long data type 64-bit signed two's complement integer. has minimum value of -9,223,372,036,854,775,808 , maximum value of 9,223,372,036,854,775,807 (inclusive). use data type when need range of values wider provided int.

as may know basic computer science or discrete math, there 2^64 possible values long, since 64 bits. , know discrete math or number theory or common sense, if there's finitely many possibilities, 1 of them has largest. long.max_value. asking tantamount "is there integer that's >0 , < 1?" mathematically nonsensical.

if need real use biginteger class.


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