c# - Merge duplicate datatable records into XML document -


i have datatable category/subcategory records in format below:

hierarchy  id1   cat1   id2    cat2         id3    cat3         4  3105  mens   3195    shorts      3130    shorts         4  3105  mens   3195    shorts      3196    swim shorts         4  3105  mens   3177    knitwear    3118    jumpers         4  3105  mens   3177    knitwear    3178    cardigans         4  3105  mens   3177    knitwear    3814    v-neck knitwear

i'm trying convert xml in format this:

<category  name="mens">         <categories name="shorts" />             <categories name="shorts" />             <categories name="swimshorts" />         <categories name="knitwear" />            <categories name="jumpers" />            <categories name="cardigans" />            <categories name="v-neck knitwear" />

but best can this:

 <category  name="mens">         <categories name="knits" />         <categories name="crew neck knitwear" />  </category>  <category name="mens">         <categories name="knits" />         <categories name="cardigans" />

as can see there duplicates don't want. know need merge or de-duplicate somehow.

i'm returning data asenumerable() , doing foreach , creating xelement top-level category , child xelements the subcategories:

var e = new xelement("category", new xattribute("id", item["did1"]), new xattribute("name", item["name1"]),                         item["did2"].tostring() != "" ? new xelement("categories", new xattribute("id", item["did2"]), new xattribute("name", item["name2"])) : null,                         item["did3"].tostring() != "" ? new xelement("categories", new xattribute("id", item["did3"]), new xattribute("name", item["name3"])) : null,                         item["did4"].tostring() != "" ? new xelement("categories", new xattribute("id", item["did4"]), new xattribute("name", item["name4"])) : null                     );

i'm not fussy technique used product results.

how this

var x = item in data         group item item.cat1 g         select new xelement(             "category",             new xattribute("name", g.key),             in g             group it.cat2 k             select new xelement("categories2", new xattribute("name", k.key),                 in k.select(x=>x.cat3).distinct()                 select new xelement("categories3", new xattribute("name",i))                 )         );

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