php - CREATE TABLE IF NOT EXISTS failing when the table exists -


this question has answer here:

i have following code:

$db_host = 'localhost'; $db_port = '3306'; $db_username = 'root'; $db_password = 'root'; $db_primarydatabase = 'dsl_ams';  // connect database, using predefined database variables in /assets/repository/mysql.php $dbconnection = new mysqli($db_host, $db_username, $db_password, $db_primarydatabase);  // if there errors (if no# of errors > 1), print out error , cancel loading page via exit(); if (mysqli_connect_errno()) {     printf("could not connect mysql databse: %s\n", mysqli_connect_error());     exit(); }  $querycreateuserstable = "create table if not exists `users` (     `id` int(11) unsigned not null auto_increment,     `email` varchar(255) not null default '',     `password` varchar(255) not null default '',     `permission_level` tinyint(1) unsigned not null default '1',     `application_completed` boolean not null default '0',     `application_in_progress` boolean not null default '0',     primary key  (`id`) )";  if(!$dbconnection->query($querycreateuserstable)){     echo "table creation failed: (" . $dbconnection->errno . ") " . $dbconnection->error; }

which outputs...

table creation failed: (1050) table '`dsl_ams`.`users`' exists

what don't understand is: isn't if not exists supposed cancel execution of sql query if table exists? in other words, if table exists, shouldn't exit if statement , not echo out @ all, , not attempt execute query?

just trying find best way "create table if doesn't exist" without outputting user.

you should warning, not error. version running? anyway if want display erros type before sql query: set sql_notes = 0; , type set sql notes=1; after query.


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