ios - How to correctly transliterate Cyrillic, without diacritics, using CFStringTransform? -
i trying use cfstringtransform transliterate names entered in russian safe ascii credit card processing. however, when stripping diacritics č becomes c, not transliteration. there anyway can use cfstringtransform, without diacritics? in other words, ч, should return ch, it's supposed in every standard http://en.wikipedia.org/wiki/romanization_of_russian
nsmutablestring *name = [@"романчук" mutablecopy]; cfmutablestringref nameref = (__bridge cfmutablestringref)name; cfstringtransform(nameref, null, kcfstringtransformtolatin, false); //name romančuk cfstringtransform(nameref, null, kcfstringtransformstripcombiningmarks, false); //name romancuk
create category nsstring , add these methods:
- (nsstring *)tolatinwithdictionary { nsmutablestring *newstring = [nsmutablestring string]; nsrange range; nsstring *symbol; nsstring *newsymbol; (nsuinteger = 0; < [self length]; ++) { // take regular symbol range = nsmakerange(i, 1); symbol = [self substringwithrange:range]; newsymbol = [self transliteratechar:symbol]; if (newsymbol != nil) { [newstring appendstring:newsymbol]; } else { [newstring appendstring:symbol]; } } return [nsstring stringwithstring:newstring]; } - (nsstring *)transliteratechar:(nsstring *)symbol { // simlicity there nsarray *cyrillicchars = @[@"а", @"б", @"в", @"г", @"д", @"е", @"ё", @"ж", @"з", @"и", @"й", @"к", @"л", @"м", @"н", @"о", @"п", @"р", @"с", @"т", @"у", @"ф", @"х", @"ц", @"ч", @"ш", @"щ", @"ъ", @"ы", @"ь", @"э", @"ю", @"я"]; nsarray *latinchars = @[@"a", @"b", @"v", @"g", @"d", @"e", @"yo", @"zh", @"z", @"i", @"y", @"k", @"l", @"m", @"n", @"o", @"p", @"r", @"s", @"t", @"u", @"f", @"h", @"ts", @"ch", @"sh", @"shch", @"'", @"y", @"'", @"e", @"yu", @"ya"]; nsdictionary *convertdict = [nsdictionary dictionarywithobjects:latinchars forkeys:cyrillicchars]; return [convertdict valueforkey:[symbol lowercasestring]]; }
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