java - Creating a Custom Exception -

i'm trying create method f1(x) throws exception when x equals 5. after try call method method f2() invoke exception. have have f2() recover calling f1(x+1). tried coding something, i'm stuck. here code:

public class fiveexception extends exception {  public void f1(int x) throws fiveexception {     if (x == 5) {         throw new fiveexception();     } }  public void f2() {     int x = 5;     try {         f1(x);     }catch (fiveexception e) {         system.out.println("x 5");     }  }   public static void main(string[] args) {     fiveexception x5 = new fiveexception();     x5.f2(); }  } 

the print statement works, i'm not sure how call f(x+1). on how fix , techniques write exceptions appreciated.

because f1 throws fiveexception, wherever call f1 must either catch exception or throw method calling method raises exception. example:

public static void main(string[] args) throws fiveexception {     fiveexception x5 = new fiveexception();     x5.f1(1); } 

or:

public static void main(string[] args) {     fiveexception x5 = new fiveexception();      try {         x5.f1(1);     } catch (fiveexception e) {         e.printstacktrace();     } } 

but code confusing... normally, isn't exception class throws itself, have other classes throw exception class.

if it's being invoked inside catch statement, must surround try-catch, 'cause code inside catch isn't protected, this:

public void f2() {     int x = 5;     try {         f1(x);     }catch (fiveexception e) {        system.out.println("x 5");        try {            f1(x + 1);        } catch (fiveexception e) {            e.printstacktrace();        }     } } 

but code ugly, can write following:

public void f2() {     int x = 5;     fprotected(x);     fprotected(x + 1); }  private void fprotected(int x) {     try {         f1(x);     }catch (fiveexception e) {        system.out.println("x 5");     } }