count - XSLT on each looped node, output number of preceding nodes containing a specific element -


given xml

<employee>   <record>     <id>1</id>     <amount>10</amount>   </record>   <record>     <id>2</id>     <amount>0</amount>   </record>   <record>     <id>3</id>     <amount>0</amount>   </record>   <record>     <id>4</id>     <amount>20</amount>   </record>   <record>     <id>5</id>     <amount>50</amount>   </record>   <record>     <id>6</id>     <amount>0</amount>   </record>   <record>     <id>7</id>     <amount>40</amount>   </record> </employee>

using xslt 1.0, want output follows:

zero amount node: 0 0 amount node: 0 0 amount node: 1 0 amount node: 2 0 amount node: 2 0 amount node: 2 0 amount node: 3

i want use for-each , loop in record nodes , on each iteration, output number of preceding nodes contained 0 amount.

my xslt: 

  <xsl:output method="text" indent="no"/>    <xsl:template match="/">    <xsl:for-each select="employee/record">      <xsl:variable name="amount-so-far" select=". | preceding-sibling::record"/>     <xsl:variable name="amount-so-far-not-zero" select="$amount-so-far[not('0' = preceding-sibling::record/amount)]"/>     <xsl:value-of select="count($amount-so-far-not-zero)"/>      <xsl:text> </xsl:text>  </xsl:for-each>  </xsl:template> </xsl:stylesheet>

try xslt desired output:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">    <xsl:template match="employee">     <xsl:for-each select="record">       <xsl:value-of select="concat('zero amount node: ', count(preceding-sibling::record[amount='0']))"/><xsl:text>        </xsl:text>     </xsl:for-each>   </xsl:template> </xsl:stylesheet>

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