php - Onclick save textarea content into database and display the content in another page -


i using ajax save textarea conent in database:

$("#update").click(function(e) {       e.preventdefault();       var ttle = $("#title").val();        var text = $("#prjdesc").val();       var datastring = 'param='+text+'&param1='+ttle;       $.ajax({         type:'post',         data:datastring,         url:'insert.php',         success:function(data) {           alert(data);         }       });     });

insert.php:

mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select db");   $name = $_post['param'];  $title = $_post['param1'];  $sql="insert $tbl_name (title, content) values ('$name','$title')";   if(mysql_query($sql)) {   echo "success";   } else {   echo "cannot insert";    }

i alerting success message when data saved. need know how displayed on page when data saved.

how done?

check out,

$("#update").click(function(e) {       e.preventdefault();       var ttle = $("#title").val();        var text = $("#prjdesc").val();       var datastring = 'param='+text+'&param1='+ttle;       $.ajax({         type:'post',         data:datastring,         url:'insert.php',         success:function(id) {           window.location ="path.php?id="+id; // redirects         }       });     });

insert.php

mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select db");   $name = $_post['param'];  $title = $_post['param1'];  $sql="insert $tbl_name (title, content) values ('$name','$title')";   if(mysql_query($sql)) {   echo mysql_insert_id(); // last inserted id   } else {   echo "cannot insert";   }

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