c++ - Reading multiple files, and keeping a set of data for each file. -


i want read file , save header in variable when rewriting(overwriting) file, can paste header , carry on printing rest of modified file. header, in case, not change can afford print out. here code inside class:

. . . static char headerline[1024];  static int read(const char* filename){ fget(var,...;     (int i=0; i<1024; ++i){         headerline[i] = var[i];     }     . . . }  int write(filename){ fprintf(filename, headerline); //printing rest of file . . . }

the code prints line saved while reading file. however, problem saves header of file read last time. if have 2 files opened , want save first one, header of second file written first one. how can avoid that? if static map solution, that?

secondly, best way print whole header(5-8 lines) instead of 1 line doing now.

so, problem needs solving reading multiple files, , want keep set of data each file.

there many ways solve this. 1 of connect filename header. suggested in comment, using std::map<std::string, std::string> 1 way that. 

static std::map<std::string, std::string> headermap;    static int read(const char* filename){ static char headerline; fget(var,...;     (int i=0; i<1024; ++i){         headerline[i] = var[i];     }        headermap[std::string(filename)] = std::string(headerline);  ...  int write(filename){   const char *headerline = headermap[std::string(filename)].c_str();  fprintf(filename, headerline);    // note printf based on above post - it's wrong,  // i'm not sure actual code does.

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