tsql - SQL Server - Finding the first day of the week -


i've been looking around chunk of code find first day of current week, , everywhere see this:

dateadd(wk, datediff(wk,0,getdate()),0)

every place says code i'm looking for.

the problem piece of code if run sunday chooses following monday.

if run:

select getdate() , dateadd(wk, datediff(wk,0,getdate()),0)

results today (tuesday):

2013-05-14 09:36:39.650................2013-05-13 00:00:00.000

this correct, chooses monday 13th.

if run: 

select getdate()-1 , dateadd(wk, datediff(wk,0,getdate()-1),0)

results yesterday (monday):

2013-05-13 09:38:57.950................2013-05-13 00:00:00.000

this correct, chooses monday 13th.

if run: 

select getdate()-2 , dateadd(wk, datediff(wk,0,getdate()-2),0)

results 12th (sunday):

2013-05-12 09:40:14.817................2013-05-13 00:00:00.000

this not correct, chooses monday 13th when should choose previous monday, 6th.

can illuminate me what's going in here? find hard believe no 1 has pointed out doesn't work, i'm wondering i'm missing.

try 1 -

set datefirst 1  declare @date datetime select @date = getdate()  select cast(dateadd(day, 1 - datepart(weekday, @date), @date) date)  select cast(@date - 2 date), cast(dateadd(wk, datediff(wk, 0, @date-2), 0) date)

results:

---------- ---------- 2013-05-12 2013-05-13

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