PHP using variables outside of a function -

i wondering if me out.

i'm writing php functions use variable inside function , use updated variable outside of function.

eg

$subtotal += $pricetoshow * $ct_qty; admincharge($subtotal); function admincharge($loggedinfoprice, $subtotal){     if (($loggedinfoprice == 5)||($loggedinfoprice == 6)){     $packagingcurrency = "$";     $packagingprice = "63";     $packagingpricing = $packagingcurrency.$packagingprice; }else {     $packagingcurrency = "£";     $packagingprice = "30";     $packagingpricing = $packagingcurrency.$packagingprice; } if(isset($packagingprice)){     $subtotal = $subtotal + $packagingprice; } }  <?php echo $subtotal; ?> 

the echo'd $subtotal seems show value before function.

is possible extract both $subtotal , $packagingpricing function?

thanks in advance.

updated function

function admincharge(&$subtotal){ // things } 

or

$subtotal = admincharge($subtotal); function admincharge($subtotal){  //do things  return $subtotal; } 

in first case, pass $subtotal variable reference, all changes reflected "outside" variable.

in second case, pass , return new value, easy understand why working.

please, pay attention

first solution - - can lead side effect difficult understand , debug

update

if want "extract" (so return) 2 variables, can following

list($subtotal,$packagingprice) = admincharge($subtotal); function admincharge($subtotal){     if(isset($packagingprice)){         $subtotal = $subtotal + $packagingprice;     }     return array($subtotal, $packagingprice); }