sql - "Union Operation not allowed in sub query" is there a way to fix this in one single query? -


this query dose not work in access 2000

select (members.first_name + " " + members.last_name)as member, (select friend_e_mail,    friends,members my_e_mail = ? , friend_e_mail <> ? union select my_e_mail,from  friends,members   friend_e_mail = ?and my_e_mail <> ?)  e_mail , (members.first_name) name  members,friends 

sample tables

members(all varchar)     data first_name               alester jude carl jones last_name                      b    c    j  friends(all varchar) my_e_mail               alester@lam.com alester@lam.com  alester@lam.com friend_e_mail           jude@lam.com    carl@lam.com   jones@lam.com 

desired output if ("?" in above query is: jones@lam.com)

+--------------+-----------+------------+ |member        |e_mail     |  name      | +---------------------------------------+  alester   alester@lam.com  alester 

desired output if("?" in above query is: alester@lam.com)

+--------------+-----------+------------+ |member        |e_mail     |  name      | +---------------------------------------+  jude b        jude@lam.com  jude  carl c        carl@lam.com  carl  jones j       jones@lam.com jones 

ps "?" query string parameters im passing in "?" know works fine.

my question : keep getting error "operation not allowed in sub query"

is work around query can use without using stored procedure or using multiple queries since needs 1 single query!?

thanks.

you can´t return more 1 row in select subquery. case have use case expression.

you have this:

select (m.first_name + " " + m.last_name) member,        case         when f1.my_email null          f2.my_e_mail         else f1.friend_email         end email,        m.first_name name members m left outer join friends f1   on m.email = f1.my_e_mail   , f1.friend_e_mail = ? left outer join friends f2   on m.email = f2.friend_e_mail   , f2.my_e_mail = ?; 

thys way return row each friend. can see names of fields not good, try refactory it. my_e_mais isn´t representative.


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