f# - How to write an infix function -

is there way write infix function not using symbols? this:

let mod x y = x % y x mod y 

maybe keyword before "mod" or something.

the existing answer correct - cannot define infix function in f# (just custom infix operator). aside trick pipe operators, can use extension members:

// define extension member 'modulo'  // can called on int32 value type system.int32   member x.modulo n = x % n  // use it, can write this: 10 .modulo 3 

note space before . needed, because otherwise compiler tries interpret 10.m numeric literal (like 10.0f).

i find bit more elegant using pipeline trick, because f# supports both functional style , object-oriented style , extension methods - in sense - close equivalent implicit operators functional style. pipeline trick looks slight misuse of operators (and may confusing @ first - perhaps more confusing method invocation).

that said, have seen people using other operators instead of pipeline - perhaps interesting version 1 (which uses fact can omit spaces around operators):

// define custom operators make syntax prettier let (</) b = |> b let (/>) b = <| b     let modulo b = % b   // can turn function infix using: 10 </modulo/> 3 

but not established idiom in f# world, still prefer extension members.