Displaying Dynamic Results PHP mySQL -


i have problem sql picking column name value instead of name itself.

so example result returned shows 

select ll_project.project_id, ll_project.size, ll_lessons.lesson_title ll_project inner join ll_lessons on ll_project.project_id = ll_lessons.project_id ll_project.project_id = bskyb5555 unknown column 'bskyb5555' in 'where clause'

from following code

$pid = $_post['project_id'] ; $psize = $_post['projectsize'] ; $pdepts = $_post['depts'] ; $lstage = $_post['stage'] ; $ltype = $_post['type'] ; $impacted = $_post['impacted'] ; //your columns in db  $columns = array('project_id'=>'ll_project.project_id','projectsize'=>'ll_project.size','depts'=>'ll_project.deptartment','stage'=>'ll_lessons.stage','type'=>'ll_lessons.type','impacted'=>'impacted');   $sqlstring = null; echo "total number of captured post variables is:"; echo count($_post); echo '<br />';  $number = 0; $querystr = "";  $prestr = array();  foreach ($_post $key => $val ) {  if (!empty($_post[$key])){        if(!is_array($_post[$key]))            $currentstr = $columns[$key]." = ".$val;         else        $currentstr = $columns[$key]." in (".implode(',',$_post[$key]).")";         $prestr[] = $currentstr;     }  } $querystr = "select ll_project.project_id, ll_project.size, ll_lessons.lesson_title ll_project inner join ll_lessons on ll_project.project_id = ll_lessons.project_id  ".implode(' , ',$prestr);  echo $querystr;  echo '<br />'; if($number ==1) { }else{ }  $result = mysql_query($querystr) or die(mysql_error());  while($row = mysql_fetch_assoc($result)) {  echo ' <tr> <td>'.$row['project_name'].' </td> <td>'.$row['project_id']. '';   }

what doing wrong , why picking value column name?

add quotes around query value

select ll_project.project_id, ll_project.size, ll_lessons.lesson_title ll_project inner join ll_lessons on ll_project.project_id = ll_lessons.project_id ll_project.project_id = "bskyb5555"

as there no quoting, not treat string

edit

unfortunately code , logic little hard follow there no commenting

you can try replacing

$currentstr = $columns[$key]." = ".$val;

with

$currentstr = $columns[$key]." = '".mysql_real_escape_string($val)."'";

this should solve issue , remove sql injection vulnerability have using user input directly in query.


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